Base | Representation |
---|---|
bin | 1110100110100111111101… |
… | …10011100001100011101001 |
3 | 11012201000102120112022111020 |
4 | 13103103332303201203221 |
5 | 13202121321302041203 |
6 | 152144414312323053 |
7 | 6523056144525441 |
oct | 723237663414351 |
9 | 135630376468436 |
10 | 32113450424553 |
11 | a261268628a93 |
12 | 37279756a3489 |
13 | 14bc392c9ca44 |
14 | 7d0429395121 |
15 | 3aa527c67153 |
hex | 1d34fece18e9 |
32113450424553 has 4 divisors (see below), whose sum is σ = 42817933899408. Its totient is φ = 21408966949700.
The previous prime is 32113450424483. The next prime is 32113450424611. The reversal of 32113450424553 is 35542405431123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 32113450424553 - 232 = 32109155457257 is a prime.
It is not an unprimeable number, because it can be changed into a prime (32113450024553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5352241737423 + ... + 5352241737428.
It is an arithmetic number, because the mean of its divisors is an integer number (10704483474852).
Almost surely, 232113450424553 is an apocalyptic number.
It is an amenable number.
32113450424553 is a deficient number, since it is larger than the sum of its proper divisors (10704483474855).
32113450424553 is a wasteful number, since it uses less digits than its factorization.
32113450424553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10704483474854.
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 32113450424553 its reverse (35542405431123), we get a palindrome (67655855855676).
The spelling of 32113450424553 in words is "thirty-two trillion, one hundred thirteen billion, four hundred fifty million, four hundred twenty-four thousand, five hundred fifty-three".
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