Base | Representation |
---|---|
bin | 1110100110111001111101… |
… | …01111101101011101001011 |
3 | 11012201221100222120010212112 |
4 | 13103130332233231131023 |
5 | 13202301113423214011 |
6 | 152153053205132535 |
7 | 6523550455111253 |
oct | 723347657553513 |
9 | 135657328503775 |
10 | 32123113101131 |
11 | a265376996a08 |
12 | 37298116ba14b |
13 | 14c0272b21c50 |
14 | 7d0aa47ca963 |
15 | 3aa8e11e258b |
hex | 1d373ebed74b |
32123113101131 has 16 divisors (see below), whose sum is σ = 35107296928704. Its totient is φ = 29215162698624.
The previous prime is 32123113101091. The next prime is 32123113101181. The reversal of 32123113101131 is 13110131132123.
It is a cyclic number.
It is not a de Polignac number, because 32123113101131 - 234 = 32105933231947 is a prime.
It is a super-2 number, since 2×321231131011312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32123113101097 and 32123113101106.
It is not an unprimeable number, because it can be changed into a prime (32123113101181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60625496 + ... + 61153061.
It is an arithmetic number, because the mean of its divisors is an integer number (2194206058044).
Almost surely, 232123113101131 is an apocalyptic number.
32123113101131 is a deficient number, since it is larger than the sum of its proper divisors (2984183827573).
32123113101131 is a wasteful number, since it uses less digits than its factorization.
32123113101131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121778870.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 32123113101131 its reverse (13110131132123), we get a palindrome (45233244233254).
The spelling of 32123113101131 in words is "thirty-two trillion, one hundred twenty-three billion, one hundred thirteen million, one hundred one thousand, one hundred thirty-one".
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