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3212561136113 = 7458937305159
BaseRepresentation
bin101110101111111011100…
…100001011100111110001
3102101010011220112210022222
4232233323210023213301
5410113311122323423
610455455154210425
7451046155050140
oct56577344134761
912333156483288
103212561136113
1110294920123aa
1243a748283a15
131a3c35322aa4
14b16bb343757
155887582b3c8
hex2ebfb90b9f1

3212561136113 has 4 divisors (see below), whose sum is σ = 3671498441280. Its totient is φ = 2753623830948.

The previous prime is 3212561136089. The next prime is 3212561136157. The reversal of 3212561136113 is 3116311652123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3212561136113 - 228 = 3212292700657 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3212561136193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229468652573 + ... + 229468652586.

It is an arithmetic number, because the mean of its divisors is an integer number (917874610320).

Almost surely, 23212561136113 is an apocalyptic number.

It is an amenable number.

3212561136113 is a deficient number, since it is larger than the sum of its proper divisors (458937305167).

3212561136113 is an equidigital number, since it uses as much as digits as its factorization.

3212561136113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 458937305166.

The product of its digits is 19440, while the sum is 35.

Adding to 3212561136113 its reverse (3116311652123), we get a palindrome (6328872788236).

The spelling of 3212561136113 in words is "three trillion, two hundred twelve billion, five hundred sixty-one million, one hundred thirty-six thousand, one hundred thirteen".

Divisors: 1 7 458937305159 3212561136113