Base | Representation |
---|---|
bin | 101110110000010101110… |
… | …010111001001001001011 |
3 | 102101011022120121100202222 |
4 | 232300111302321021023 |
5 | 410120211301401303 |
6 | 10500010554244255 |
7 | 451063110404624 |
oct | 56602562711113 |
9 | 12334276540688 |
10 | 3213001200203 |
11 | 1029698462033 |
12 | 43a84b72668b |
13 | 1a3ca5551142 |
14 | b171d976a4b |
15 | 5889e2a5938 |
hex | 2ec15cb924b |
3213001200203 has 8 divisors (see below), whose sum is σ = 3266887974240. Its totient is φ = 3159153607680.
The previous prime is 3213001200187. The next prime is 3213001200287. The reversal of 3213001200203 is 3020021003123.
3213001200203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3213001200203 - 24 = 3213001200187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3213001220203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9629975 + ... + 9958032.
It is an arithmetic number, because the mean of its divisors is an integer number (408360996780).
Almost surely, 23213001200203 is an apocalyptic number.
3213001200203 is a deficient number, since it is larger than the sum of its proper divisors (53886774037).
3213001200203 is a wasteful number, since it uses less digits than its factorization.
3213001200203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19590757.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 3213001200203 its reverse (3020021003123), we get a palindrome (6233022203326).
The spelling of 3213001200203 in words is "three trillion, two hundred thirteen billion, one million, two hundred thousand, two hundred three".
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