3213032102113 has 4 divisors (see below), whose sum is σ = 3213155143360. Its totient is φ = 3212909060868.

The previous prime is 3213032102047. The next prime is 3213032102129. The reversal of 3213032102113 is 3112012303123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3213032102113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3213032102143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61481445 + ... + 61533682.

It is an arithmetic number, because the mean of its divisors is an integer number (803288785840).

Almost surely, 2^{3213032102113} is an apocalyptic number.

It is an amenable number.

3213032102113 is a deficient number, since it is larger than the sum of its proper divisors (123041247).

3213032102113 is a wasteful number, since it uses less digits than its factorization.

3213032102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123041246.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 3213032102113 its reverse (3112012303123), we get a palindrome (6325044405236).

The spelling of 3213032102113 in words is "three trillion, two hundred thirteen billion, thirty-two million, one hundred two thousand, one hundred thirteen".