Base | Representation |
---|---|
bin | 1110100111010000110111… |
… | …11100110000110010111011 |
3 | 11012210010010021021211102011 |
4 | 13103220123330300302323 |
5 | 13203001312020101021 |
6 | 152202445552550351 |
7 | 6524464343653402 |
oct | 723503374606273 |
9 | 135703107254364 |
10 | 32135414222011 |
11 | a26a609618111 |
12 | 37300852523b7 |
13 | 14c14834877b9 |
14 | 7d15103d0639 |
15 | 3aadb10e3de1 |
hex | 1d3a1bf30cbb |
32135414222011 has 4 divisors (see below), whose sum is σ = 33003938930752. Its totient is φ = 31266889513272.
The previous prime is 32135414222003. The next prime is 32135414222029. The reversal of 32135414222011 is 11022241453123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32135414222011 - 23 = 32135414222003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32135414220011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434262354315 + ... + 434262354388.
It is an arithmetic number, because the mean of its divisors is an integer number (8250984732688).
Almost surely, 232135414222011 is an apocalyptic number.
32135414222011 is a deficient number, since it is larger than the sum of its proper divisors (868524708741).
32135414222011 is an equidigital number, since it uses as much as digits as its factorization.
32135414222011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 868524708740.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 32135414222011 its reverse (11022241453123), we get a palindrome (43157655675134).
The spelling of 32135414222011 in words is "thirty-two trillion, one hundred thirty-five billion, four hundred fourteen million, two hundred twenty-two thousand, eleven".
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