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3214313002003 = 8980701447527
BaseRepresentation
bin101110110001100011111…
…111000001010000010011
3102101021200222222210112211
4232301203333001100103
5410130403112031003
610500345054532551
7451140446500645
oct56614377012023
912337628883484
103214313002003
11102a200990154
1243ab56b07157
131a415425bb1c
14b1805c8a895
155892952796d
hex2ec63fc1413

3214313002003 has 8 divisors (see below), whose sum is σ = 3250476419040. Its totient is φ = 3178150641600.

The previous prime is 3214313001973. The next prime is 3214313002063. The reversal of 3214313002003 is 3002003134123.

3214313002003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3214313002003 - 233 = 3205723067411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3214313002063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6958626 + ... + 7406152.

It is an arithmetic number, because the mean of its divisors is an integer number (406309552380).

Almost surely, 23214313002003 is an apocalyptic number.

3214313002003 is a deficient number, since it is larger than the sum of its proper divisors (36163417037).

3214313002003 is an equidigital number, since it uses as much as digits as its factorization.

3214313002003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 528317.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 3214313002003 its reverse (3002003134123), we get a palindrome (6216316136126).

The spelling of 3214313002003 in words is "three trillion, two hundred fourteen billion, three hundred thirteen million, two thousand, three".

Divisors: 1 89 80701 447527 7182389 39829903 36115876427 3214313002003