Base | Representation |
---|---|
bin | 101110110110111110101… |
… | …101100100010110100001 |
3 | 102101211201101221001211001 |
4 | 232312332231210112201 |
5 | 410224311302333441 |
6 | 10503150215552001 |
7 | 451434553261624 |
oct | 56667655442641 |
9 | 12354641831731 |
10 | 3220130121121 |
11 | 1031716560911 |
12 | 4400bb08b601 |
13 | 1a4870485644 |
14 | b1bd8691dbb |
15 | 58b6a088731 |
hex | 2edbeb645a1 |
3220130121121 has 8 divisors (see below), whose sum is σ = 3223364489280. Its totient is φ = 3216896754192.
The previous prime is 3220130121083. The next prime is 3220130121127. The reversal of 3220130121121 is 1211210310223.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3220130121121 - 239 = 2670374307233 is a prime.
It is a super-3 number, since 3×32201301211213 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3220130121127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6270346 + ... + 6764428.
It is an arithmetic number, because the mean of its divisors is an integer number (402920561160).
Almost surely, 23220130121121 is an apocalyptic number.
It is an amenable number.
3220130121121 is a deficient number, since it is larger than the sum of its proper divisors (3234368159).
3220130121121 is a wasteful number, since it uses less digits than its factorization.
3220130121121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500615.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 3220130121121 its reverse (1211210310223), we get a palindrome (4431340431344).
The spelling of 3220130121121 in words is "three trillion, two hundred twenty billion, one hundred thirty million, one hundred twenty-one thousand, one hundred twenty-one".
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