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3221220113 = 26091234657
BaseRepresentation
bin1011111111111111…
…1110101100010001
322022111021221021122
42333333332230101
523044113020423
61251345532025
7142552630166
oct27777765421
98274257248
103221220113
111403327391
1275a944015
133c448b407
14227b5006d
1513cbe08c8
hexbfffeb11

3221220113 has 4 divisors (see below), whose sum is σ = 3222457380. Its totient is φ = 3219982848.

The previous prime is 3221220083. The next prime is 3221220161. The reversal of 3221220113 is 3110221223.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3110221223 = 28310990181.

It can be written as a sum of positive squares in 2 ways, for example, as 1972869889 + 1248350224 = 44417^2 + 35332^2 .

It is a cyclic number.

It is not a de Polignac number, because 3221220113 - 214 = 3221203729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3221220091 and 3221220100.

It is not an unprimeable number, because it can be changed into a prime (3221220313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 614720 + ... + 619937.

It is an arithmetic number, because the mean of its divisors is an integer number (805614345).

Almost surely, 23221220113 is an apocalyptic number.

It is an amenable number.

3221220113 is a deficient number, since it is larger than the sum of its proper divisors (1237267).

3221220113 is a wasteful number, since it uses less digits than its factorization.

3221220113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1237266.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3221220113 is about 56755.7936513974. The cubic root of 3221220113 is about 1476.8627409984.

Adding to 3221220113 its reverse (3110221223), we get a palindrome (6331441336).

It can be divided in two parts, 32212 and 20113, that added together give a palindrome (52325).

The spelling of 3221220113 in words is "three billion, two hundred twenty-one million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 2609 1234657 3221220113