Base | Representation |
---|---|
bin | 1110101001100001100110… |
… | …01010000101000001000011 |
3 | 11020001112200020020201021101 |
4 | 13110300303022011001003 |
5 | 13210234423412000003 |
6 | 152302255543235231 |
7 | 6533214653454055 |
oct | 724606312050103 |
9 | 136045606221241 |
10 | 32213113000003 |
11 | a29a560549021 |
12 | 374314a448b17 |
13 | 14c88b690a190 |
14 | 7d51a169d8d5 |
15 | 3ace0c54e11d |
hex | 1d4c33285043 |
32213113000003 has 8 divisors (see below), whose sum is σ = 34691912410400. Its totient is φ = 29734437538368.
The previous prime is 32213112999973. The next prime is 32213113000037. The reversal of 32213113000003 is 30000031131223.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 32213113000003 - 29 = 32213112999491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32213113000073) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30447063 + ... + 31487296.
It is an arithmetic number, because the mean of its divisors is an integer number (4336489051300).
Almost surely, 232213113000003 is an apocalyptic number.
32213113000003 is a deficient number, since it is larger than the sum of its proper divisors (2478799410397).
32213113000003 is a wasteful number, since it uses less digits than its factorization.
32213113000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61974381.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 32213113000003 its reverse (30000031131223), we get a palindrome (62213144131226).
The spelling of 32213113000003 in words is "thirty-two trillion, two hundred thirteen billion, one hundred thirteen million, three", and thus it is an aban number.
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