3221400113 has 4 divisors (see below), whose sum is σ = 3224678208. Its totient is φ = 3218122020.

The previous prime is 3221400109. The next prime is 3221400121. The reversal of 3221400113 is 3110041223.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110041223 = 39439 ⋅78857.

It is a cyclic number.

It is not a de Polignac number, because 3221400113 - 2² = 3221400109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3221400091 and 3221400100.

It is not an unprimeable number, because it can be changed into a prime (3221400313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1637573 + ... + 1639538.

It is an arithmetic number, because the mean of its divisors is an integer number (806169552).

Almost surely, 2^3221400113 is an apocalyptic number.

It is an amenable number.

3221400113 is a deficient number, since it is larger than the sum of its proper divisors (3278095).

3221400113 is an equidigital number, since it uses as much as digits as its factorization.

3221400113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3278094.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3221400113 is about 56757.3793704396. The cubic root of 3221400113 is about 1476.8902492440.

Adding to 3221400113 its reverse (3110041223), we get a palindrome (6331441336).

The spelling of 3221400113 in words is "three billion, two hundred twenty-one million, four hundred thousand, one hundred thirteen".