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3223132012993 = 21521149766833
BaseRepresentation
bin101110111001110001101…
…000111000000111000001
3102102010110121111222022111
4232321301220320013001
5410301433243403433
610504404132535321
7451602134034154
oct56716150700701
912363417458274
103223132012993
111032a16aa3692
124407b8481541
131a4c2b380019
14b200122bc9b
1558c938a2dcd
hex2ee71a381c1

3223132012993 has 4 divisors (see below), whose sum is σ = 3223281801348. Its totient is φ = 3222982224640.

The previous prime is 3223132012979. The next prime is 3223132013029. The reversal of 3223132012993 is 3992102313223.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2285155258929 + 937976754064 = 1511673^2 + 968492^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3223132012993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3223132015993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74861896 + ... + 74904937.

It is an arithmetic number, because the mean of its divisors is an integer number (805820450337).

Almost surely, 23223132012993 is an apocalyptic number.

It is an amenable number.

3223132012993 is a deficient number, since it is larger than the sum of its proper divisors (149788355).

3223132012993 is a wasteful number, since it uses less digits than its factorization.

3223132012993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149788354.

The product of its (nonzero) digits is 104976, while the sum is 40.

The spelling of 3223132012993 in words is "three trillion, two hundred twenty-three billion, one hundred thirty-two million, twelve thousand, nine hundred ninety-three".

Divisors: 1 21521 149766833 3223132012993