Base | Representation |
---|---|
bin | 101110111010111101001… |
… | …111001110000011011001 |
3 | 102102020202000010110012120 |
4 | 232322331033032003121 |
5 | 410312032442334140 |
6 | 10505134041531453 |
7 | 451645434543645 |
oct | 56727517160331 |
9 | 12366660113176 |
10 | 3224400355545 |
11 | 1033507a39176 |
12 | 440ab11a3b89 |
13 | 1a50a1082785 |
14 | b20c186bc25 |
15 | 58d19ddd1d0 |
hex | 2eebd3ce0d9 |
3224400355545 has 16 divisors (see below), whose sum is σ = 5325461233152. Its totient is φ = 1664206634880.
The previous prime is 3224400355543. The next prime is 3224400355559. The reversal of 3224400355545 is 5455530044223.
It is not a de Polignac number, because 3224400355545 - 21 = 3224400355543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3224400355497 and 3224400355506.
It is not an unprimeable number, because it can be changed into a prime (3224400355543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3467096692 + ... + 3467097621.
It is an arithmetic number, because the mean of its divisors is an integer number (332841327072).
Almost surely, 23224400355545 is an apocalyptic number.
It is an amenable number.
3224400355545 is a deficient number, since it is larger than the sum of its proper divisors (2101060877607).
3224400355545 is a wasteful number, since it uses less digits than its factorization.
3224400355545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6934194352.
The product of its (nonzero) digits is 1440000, while the sum is 42.
Adding to 3224400355545 its reverse (5455530044223), we get a palindrome (8679930399768).
The spelling of 3224400355545 in words is "three trillion, two hundred twenty-four billion, four hundred million, three hundred fifty-five thousand, five hundred forty-five".
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