3225113 has 4 divisors (see below), whose sum is σ = 3228708. Its totient is φ = 3221520.

The previous prime is 3225097. The next prime is 3225127. The reversal of 3225113 is 3115223.

3225113 is nontrivially palindromic in base 11.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3115223 = 577 ⋅5399.

It can be written as a sum of positive squares in 2 ways, for example, as 446224 + 2778889 = 668^2 + 1667^2 .

It is a cyclic number.

It is not a de Polignac number, because 3225113 - 2⁴ = 3225097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3225091 and 3225100.

It is not an unprimeable number, because it can be changed into a prime (3225143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803 + ... + 2663.

It is an arithmetic number, because the mean of its divisors is an integer number (807177).

Almost surely, 2^3225113 is an apocalyptic number.

It is an amenable number.

3225113 is a deficient number, since it is larger than the sum of its proper divisors (3595).

3225113 is a wasteful number, since it uses less digits than its factorization.

3225113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3594.

The product of its digits is 180, while the sum is 17.

The square root of 3225113 is about 1795.8599611328. The cubic root of 3225113 is about 147.7457437531.

The spelling of 3225113 in words is "three million, two hundred twenty-five thousand, one hundred thirteen".