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32300220113 = 74614317159
BaseRepresentation
bin11110000101001111…
…100011111011010001
310002101001120012011122
4132011033203323101
51012122324020423
622501041452025
72222300224640
oct360517437321
9102331505148
1032300220113
11127756a5497
126315341015
133079ab64a5
1417c5b33357
15c90a408c8
hex7853e3ed1

32300220113 has 4 divisors (see below), whose sum is σ = 36914537280. Its totient is φ = 27685902948.

The previous prime is 32300220107. The next prime is 32300220143. The reversal of 32300220113 is 31102200323.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32300220113 - 26 = 32300220049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32300220091 and 32300220100.

It is not an unprimeable number, because it can be changed into a prime (32300220143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2307158573 + ... + 2307158586.

It is an arithmetic number, because the mean of its divisors is an integer number (9228634320).

Almost surely, 232300220113 is an apocalyptic number.

It is an amenable number.

32300220113 is a deficient number, since it is larger than the sum of its proper divisors (4614317167).

32300220113 is an equidigital number, since it uses as much as digits as its factorization.

32300220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4614317166.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 32300220113 its reverse (31102200323), we get a palindrome (63402420436).

The spelling of 32300220113 in words is "thirty-two billion, three hundred million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 7 4614317159 32300220113