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32303100113 = 127467954361
BaseRepresentation
bin11110000101011010…
…100011000011010001
310002101020222111210022
4132011122203003101
51012124043200423
622501223313225
72222333551304
oct360532430321
9102336874708
1032303100113
1112777292259
1263162ab815
13307a58432b
1417c6282b3b
15c90e0ddc8
hex7856a30d1

32303100113 has 8 divisors (see below), whose sum is σ = 32565012480. Its totient is φ = 32041306080.

The previous prime is 32303100101. The next prime is 32303100119. The reversal of 32303100113 is 31100130323.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 32303100113 - 212 = 32303096017 is a prime.

It is a super-2 number, since 2×323031001132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 32303100091 and 32303100100.

It is not an unprimeable number, because it can be changed into a prime (32303100119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 567053 + ... + 621413.

It is an arithmetic number, because the mean of its divisors is an integer number (4070626560).

Almost surely, 232303100113 is an apocalyptic number.

It is an amenable number.

32303100113 is a deficient number, since it is larger than the sum of its proper divisors (261912367).

32303100113 is a wasteful number, since it uses less digits than its factorization.

32303100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59167.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 32303100113 its reverse (31100130323), we get a palindrome (63403230436).

The spelling of 32303100113 in words is "thirty-two billion, three hundred three million, one hundred thousand, one hundred thirteen".

Divisors: 1 127 4679 54361 594233 6903847 254355119 32303100113