Base | Representation |
---|---|
bin | 1110101100011000100010… |
… | …10110101000010111101001 |
3 | 11020101221012011002000100011 |
4 | 13112030101112220113221 |
5 | 13213342101002104001 |
6 | 152415341541011521 |
7 | 6543262611241222 |
oct | 726142126502751 |
9 | 136357164060304 |
10 | 32311330113001 |
11 | a328181548795 |
12 | 375a19b0b3ba1 |
13 | 1504c39c3bba4 |
14 | 7d9c3ba20249 |
15 | 3b0759eb0d51 |
hex | 1d63115a85e9 |
32311330113001 has 4 divisors (see below), whose sum is σ = 32793588771472. Its totient is φ = 31829071454532.
The previous prime is 32311330112987. The next prime is 32311330113043. The reversal of 32311330113001 is 10031103311323.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 32311330113001 - 211 = 32311330110953 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32311330123001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241129329135 + ... + 241129329268.
It is an arithmetic number, because the mean of its divisors is an integer number (8198397192868).
Almost surely, 232311330113001 is an apocalyptic number.
It is an amenable number.
32311330113001 is a deficient number, since it is larger than the sum of its proper divisors (482258658471).
32311330113001 is an equidigital number, since it uses as much as digits as its factorization.
32311330113001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 482258658470.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 32311330113001 its reverse (10031103311323), we get a palindrome (42342433424324).
The spelling of 32311330113001 in words is "thirty-two trillion, three hundred eleven billion, three hundred thirty million, one hundred thirteen thousand, one".
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