Base | Representation |
---|---|
bin | 101111000010001010100… |
… | …111100101111100011001 |
3 | 102102222201110121001000111 |
4 | 233002022213211330121 |
5 | 410423411101311213 |
6 | 10512454115404321 |
7 | 452341316360203 |
oct | 57021247457431 |
9 | 12388643531014 |
10 | 3232141041433 |
11 | 103681a3a1037 |
12 | 4424b15b36a1 |
13 | 1a5a35971895 |
14 | b2617913773 |
15 | 5911e764a3d |
hex | 2f08a9e5f19 |
3232141041433 has 16 divisors (see below), whose sum is σ = 3341365163136. Its totient is φ = 3124500785280.
The previous prime is 3232141041431. The next prime is 3232141041443. The reversal of 3232141041433 is 3341401412323.
It is not a de Polignac number, because 3232141041433 - 21 = 3232141041431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3232141041395 and 3232141041404.
It is not an unprimeable number, because it can be changed into a prime (3232141041431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7410291 + ... + 7834327.
It is an arithmetic number, because the mean of its divisors is an integer number (208835322696).
Almost surely, 23232141041433 is an apocalyptic number.
It is an amenable number.
3232141041433 is a deficient number, since it is larger than the sum of its proper divisors (109224121703).
3232141041433 is a wasteful number, since it uses less digits than its factorization.
3232141041433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425904.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 3232141041433 its reverse (3341401412323), we get a palindrome (6573542453756).
The spelling of 3232141041433 in words is "three trillion, two hundred thirty-two billion, one hundred forty-one million, forty-one thousand, four hundred thirty-three".
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