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3232141041433 = 431031721424037
BaseRepresentation
bin101111000010001010100…
…111100101111100011001
3102102222201110121001000111
4233002022213211330121
5410423411101311213
610512454115404321
7452341316360203
oct57021247457431
912388643531014
103232141041433
11103681a3a1037
124424b15b36a1
131a5a35971895
14b2617913773
155911e764a3d
hex2f08a9e5f19

3232141041433 has 16 divisors (see below), whose sum is σ = 3341365163136. Its totient is φ = 3124500785280.

The previous prime is 3232141041431. The next prime is 3232141041443. The reversal of 3232141041433 is 3341401412323.

It is not a de Polignac number, because 3232141041433 - 21 = 3232141041431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3232141041395 and 3232141041404.

It is not an unprimeable number, because it can be changed into a prime (3232141041431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7410291 + ... + 7834327.

It is an arithmetic number, because the mean of its divisors is an integer number (208835322696).

Almost surely, 23232141041433 is an apocalyptic number.

It is an amenable number.

3232141041433 is a deficient number, since it is larger than the sum of its proper divisors (109224121703).

3232141041433 is a wasteful number, since it uses less digits than its factorization.

3232141041433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 425904.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 3232141041433 its reverse (3341401412323), we get a palindrome (6573542453756).

The spelling of 3232141041433 in words is "three trillion, two hundred thirty-two billion, one hundred forty-one million, forty-one thousand, four hundred thirty-three".

Divisors: 1 43 103 1721 4429 74003 177263 424037 7622309 18233591 43675811 729767677 1878059873 31380010111 75166070731 3232141041433