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323414113 = 1129401283
BaseRepresentation
bin10011010001101…
…110100001100001
3211112120010202111
4103101232201201
51130243222423
652031515321
711004655201
oct2321564141
9745503674
10323414113
111566168a0
1290388b41
13520081c9
1430d4a401
151d5d660d
hex1346e861

323414113 has 4 divisors (see below), whose sum is σ = 352815408. Its totient is φ = 294012820.

The previous prime is 323414101. The next prime is 323414141. The reversal of 323414113 is 311414323.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 323414113 - 25 = 323414081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (323414213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14700631 + ... + 14700652.

It is an arithmetic number, because the mean of its divisors is an integer number (88203852).

Almost surely, 2323414113 is an apocalyptic number.

It is an amenable number.

323414113 is a deficient number, since it is larger than the sum of its proper divisors (29401295).

323414113 is a wasteful number, since it uses less digits than its factorization.

323414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29401294.

The product of its digits is 864, while the sum is 22.

The square root of 323414113 is about 17983.7179971217. The cubic root of 323414113 is about 686.4142999407.

Adding to 323414113 its reverse (311414323), we get a palindrome (634828436).

The spelling of 323414113 in words is "three hundred twenty-three million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 11 29401283 323414113