Base | Representation |
---|---|
bin | 1110101101010111111001… |
… | …01111011100000110000001 |
3 | 11020112011222122021012000121 |
4 | 13112223330233130012001 |
5 | 13214421231033030103 |
6 | 152443125041220241 |
7 | 6545605530631204 |
oct | 726537457340601 |
9 | 136464878235017 |
10 | 32345344033153 |
11 | a3406465133a8 |
12 | 37648b2331681 |
13 | 15081caa8a668 |
14 | 7db7471a393b |
15 | 3b159b1ae6bd |
hex | 1d6afcbdc181 |
32345344033153 has 8 divisors (see below), whose sum is σ = 32376669849216. Its totient is φ = 32314033309200.
The previous prime is 32345344033141. The next prime is 32345344033181. The reversal of 32345344033153 is 35133044354323.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 32345344033153 - 221 = 32345341936001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32345344031153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 517800 + ... + 8059702.
It is an arithmetic number, because the mean of its divisors is an integer number (4047083731152).
Almost surely, 232345344033153 is an apocalyptic number.
It is an amenable number.
32345344033153 is a deficient number, since it is larger than the sum of its proper divisors (31325816063).
32345344033153 is a wasteful number, since it uses less digits than its factorization.
32345344033153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7546055.
The product of its (nonzero) digits is 2332800, while the sum is 43.
Adding to 32345344033153 its reverse (35133044354323), we get a palindrome (67478388387476).
The spelling of 32345344033153 in words is "thirty-two trillion, three hundred forty-five billion, three hundred forty-four million, thirty-three thousand, one hundred fifty-three".
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