Base | Representation |
---|---|
bin | 101111000101000100001… |
… | …010110010011001010001 |
3 | 102110021202102021101022012 |
4 | 233011010022302121101 |
5 | 411001300014134213 |
6 | 10514131042152305 |
7 | 452511416465054 |
oct | 57050412623121 |
9 | 12407672241265 |
10 | 3235254052433 |
11 | 103807762a2a7 |
12 | 443020052695 |
13 | 1a61108a3b20 |
14 | b2831136a9b |
15 | 59252bcd4a8 |
hex | 2f1442b2651 |
3235254052433 has 16 divisors (see below), whose sum is σ = 3649749618816. Its totient is φ = 2845430353920.
The previous prime is 3235254052427. The next prime is 3235254052447. The reversal of 3235254052433 is 3342504525323.
3235254052433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3235254052433 - 210 = 3235254051409 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3235254052403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20974223 + ... + 21127908.
It is an arithmetic number, because the mean of its divisors is an integer number (228109351176).
Almost surely, 23235254052433 is an apocalyptic number.
It is an amenable number.
3235254052433 is a deficient number, since it is larger than the sum of its proper divisors (414495566383).
3235254052433 is a wasteful number, since it uses less digits than its factorization.
3235254052433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42102424.
The product of its (nonzero) digits is 1296000, while the sum is 41.
Adding to 3235254052433 its reverse (3342504525323), we get a palindrome (6577758577756).
The spelling of 3235254052433 in words is "three trillion, two hundred thirty-five billion, two hundred fifty-four million, fifty-two thousand, four hundred thirty-three".
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