32400013433 has 4 divisors (see below), whose sum is σ = 32402871168. Its totient is φ = 32397155700.

The previous prime is 32400013367. The next prime is 32400013439. The reversal of 32400013433 is 33431000423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32400013433 - 2¹⁸ = 32399751289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32400013399 and 32400013408.

It is not an unprimeable number, because it can be changed into a prime (32400013439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1411793 + ... + 1434558.

It is an arithmetic number, because the mean of its divisors is an integer number (8100717792).

Almost surely, 2^32400013433 is an apocalyptic number.

It is an amenable number.

32400013433 is a deficient number, since it is larger than the sum of its proper divisors (2857735).

32400013433 is a wasteful number, since it uses less digits than its factorization.

32400013433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2857734.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 32400013433 its reverse (33431000423), we get a palindrome (65831013856).

The spelling of 32400013433 in words is "thirty-two billion, four hundred million, thirteen thousand, four hundred thirty-three".