Base | Representation |
---|---|
bin | 11110001011001100… |
… | …101000000111001001 |
3 | 10002122000112022222201 |
4 | 132023030220013021 |
5 | 1012323412122441 |
6 | 22515010520201 |
7 | 2224622266054 |
oct | 361314500711 |
9 | 102560468881 |
10 | 32400114121 |
11 | 12817024321 |
12 | 6342896061 |
13 | 30946c097b |
14 | 17d50d7a9b |
15 | c996c3c31 |
hex | 78b3281c9 |
32400114121 has 4 divisors (see below), whose sum is σ = 32404334544. Its totient is φ = 32395893700.
The previous prime is 32400114113. The next prime is 32400114137. The reversal of 32400114121 is 12141100423.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12141100423 = 769 ⋅15788167.
It is a cyclic number.
It is not a de Polignac number, because 32400114121 - 23 = 32400114113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32430114121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2098675 + ... + 2114056.
It is an arithmetic number, because the mean of its divisors is an integer number (8101083636).
Almost surely, 232400114121 is an apocalyptic number.
It is an amenable number.
32400114121 is a deficient number, since it is larger than the sum of its proper divisors (4220423).
32400114121 is an equidigital number, since it uses as much as digits as its factorization.
32400114121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4220422.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 32400114121 its reverse (12141100423), we get a palindrome (44541214544).
The spelling of 32400114121 in words is "thirty-two billion, four hundred million, one hundred fourteen thousand, one hundred twenty-one".
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