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324104413000243 = 752411943075397
BaseRepresentation
bin100100110110001010111000…
…0011010000011001000110011
31120111120002010210120202222011
41021230111300122003020303
5314440111314212001433
63105151302321223351
7125160525330415411
oct11154256032031063
91514502123522864
10324104413000243
11942a6a00832667
1230425734191b57
1310bacbb8359055
145a06a471942b1
152770a760403cd
hex126c570683233

324104413000243 has 4 divisors (see below), whose sum is σ = 324104463599760. Its totient is φ = 324104362400728.

The previous prime is 324104413000241. The next prime is 324104413000283. The reversal of 324104413000243 is 342000314401423.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 324104413000243 - 21 = 324104413000241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (324104413000241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14013580 + ... + 29061817.

It is an arithmetic number, because the mean of its divisors is an integer number (81026115899940).

Almost surely, 2324104413000243 is an apocalyptic number.

324104413000243 is a deficient number, since it is larger than the sum of its proper divisors (50599517).

324104413000243 is an equidigital number, since it uses as much as digits as its factorization.

324104413000243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50599516.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 324104413000243 its reverse (342000314401423), we get a palindrome (666104727401666).

The spelling of 324104413000243 in words is "three hundred twenty-four trillion, one hundred four billion, four hundred thirteen million, two hundred forty-three", and thus it is an aban number.

Divisors: 1 7524119 43075397 324104413000243