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3241450433 = 13249342341
BaseRepresentation
bin1100000100110100…
…1001101111000001
322100220100202001202
43001031021233001
523114302403213
61253351310545
7143216605544
oct30115115701
98326322052
103241450433
111413794761
1276567b455
133c8722610
1422a6d885b
1513e889b58
hexc1349bc1

3241450433 has 4 divisors (see below), whose sum is σ = 3490792788. Its totient is φ = 2992108080.

The previous prime is 3241450423. The next prime is 3241450441. The reversal of 3241450433 is 3340541423.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1475097649 + 1766352784 = 38407^2 + 42028^2 .

It is not a de Polignac number, because 3241450433 - 228 = 2973014977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3241450396 and 3241450405.

It is not an unprimeable number, because it can be changed into a prime (3241450423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124671158 + ... + 124671183.

It is an arithmetic number, because the mean of its divisors is an integer number (872698197).

Almost surely, 23241450433 is an apocalyptic number.

It is an amenable number.

3241450433 is a deficient number, since it is larger than the sum of its proper divisors (249342355).

3241450433 is a wasteful number, since it uses less digits than its factorization.

3241450433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249342354.

The product of its (nonzero) digits is 17280, while the sum is 29.

The square root of 3241450433 is about 56933.7372126580. The cubic root of 3241450433 is about 1479.9480187794.

Adding to 3241450433 its reverse (3340541423), we get a palindrome (6581991856).

The spelling of 3241450433 in words is "three billion, two hundred forty-one million, four hundred fifty thousand, four hundred thirty-three".

Divisors: 1 13 249342341 3241450433