Base | Representation |
---|---|
bin | 1110101111101000110010… |
… | …01001011001011010111011 |
3 | 11020210121202200022022001001 |
4 | 13113310121021121122323 |
5 | 13222210032240330243 |
6 | 152542551424505431 |
7 | 6554331246553522 |
oct | 727643111313273 |
9 | 136717680268031 |
10 | 32423130011323 |
11 | a370632693077 |
12 | 37779a077b277 |
13 | 15126462c178c |
14 | 801405c914b9 |
15 | 3b36000e1a4d |
hex | 1d7d192596bb |
32423130011323 has 4 divisors (see below), whose sum is σ = 32431655686968. Its totient is φ = 32414604335680.
The previous prime is 32423130011231. The next prime is 32423130011359. The reversal of 32423130011323 is 32311003132423.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32423130011323 - 233 = 32414540076731 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32423130011291 and 32423130011300.
It is not an unprimeable number, because it can be changed into a prime (32423130011383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4262832118 + ... + 4262839723.
It is an arithmetic number, because the mean of its divisors is an integer number (8107913921742).
Almost surely, 232423130011323 is an apocalyptic number.
32423130011323 is a deficient number, since it is larger than the sum of its proper divisors (8525675645).
32423130011323 is an equidigital number, since it uses as much as digits as its factorization.
32423130011323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8525675644.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 32423130011323 its reverse (32311003132423), we get a palindrome (64734133143746).
The spelling of 32423130011323 in words is "thirty-two trillion, four hundred twenty-three billion, one hundred thirty million, eleven thousand, three hundred twenty-three".
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