Base | Representation |
---|---|
bin | 1001011100000111011… |
… | …00011100010111010011 |
3 | 1011000011020220100200012 |
4 | 10232003230130113103 |
5 | 20303212443404021 |
6 | 404555052345135 |
7 | 32301151423646 |
oct | 4560354342723 |
9 | 1130136810605 |
10 | 324332013011 |
11 | 115603a69866 |
12 | 52a361751ab |
13 | 24779b54046 |
14 | 119aa8c5a5d |
15 | 86838d435b |
hex | 4b83b1c5d3 |
324332013011 has 4 divisors (see below), whose sum is σ = 324336756912. Its totient is φ = 324327269112.
The previous prime is 324332013007. The next prime is 324332013029. The reversal of 324332013011 is 110310233423.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 324332013011 - 22 = 324332013007 is a prime.
It is a super-2 number, since 2×3243320130112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (324332013041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2267876 + ... + 2406641.
It is an arithmetic number, because the mean of its divisors is an integer number (81084189228).
Almost surely, 2324332013011 is an apocalyptic number.
324332013011 is a deficient number, since it is larger than the sum of its proper divisors (4743901).
324332013011 is an equidigital number, since it uses as much as digits as its factorization.
324332013011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4743900.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 324332013011 its reverse (110310233423), we get a palindrome (434642246434).
The spelling of 324332013011 in words is "three hundred twenty-four billion, three hundred thirty-two million, thirteen thousand, eleven".
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