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3245372730681 = 31081790910227
BaseRepresentation
bin101111001110011111010…
…010011110110100111001
3102111020212121100111101020
4233032133102132310321
5411133010404340211
610522523104413053
7453320235024534
oct57163722366471
912436777314336
103245372730681
11104139a333004
12444b84917189
131a70640446c3
14b3110d4da1b
15596461d0306
hex2f39f49ed39

3245372730681 has 4 divisors (see below), whose sum is σ = 4327163640912. Its totient is φ = 2163581820452.

The previous prime is 3245372730679. The next prime is 3245372730707. The reversal of 3245372730681 is 1860372735423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3245372730681 - 21 = 3245372730679 is a prime.

It is a super-2 number, since 2×32453727306812 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (3245372730581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540895455111 + ... + 540895455116.

It is an arithmetic number, because the mean of its divisors is an integer number (1081790910228).

Almost surely, 23245372730681 is an apocalyptic number.

It is an amenable number.

3245372730681 is a deficient number, since it is larger than the sum of its proper divisors (1081790910231).

3245372730681 is a wasteful number, since it uses less digits than its factorization.

3245372730681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1081790910230.

The product of its (nonzero) digits is 5080320, while the sum is 51.

The spelling of 3245372730681 in words is "three trillion, two hundred forty-five billion, three hundred seventy-two million, seven hundred thirty thousand, six hundred eighty-one".

Divisors: 1 3 1081790910227 3245372730681