Base | Representation |
---|---|
bin | 101111010010010111101… |
… | …111000110000000010011 |
3 | 102111122122002122112112121 |
4 | 233102113233012000103 |
5 | 411220024442341010 |
6 | 10524452444435111 |
7 | 453525440411236 |
oct | 57222757060023 |
9 | 12448562575477 |
10 | 3249540980755 |
11 | 1043139193a83 |
12 | 445948848a97 |
13 | 1a7579784a74 |
14 | b33c877d41d |
15 | 597dc0dc3da |
hex | 2f497bc6013 |
3249540980755 has 16 divisors (see below), whose sum is σ = 4025412762624. Its totient is φ = 2515664348640.
The previous prime is 3249540980729. The next prime is 3249540980761. The reversal of 3249540980755 is 5570890459423.
3249540980755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3249540980755 - 215 = 3249540947987 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3249540980693 and 3249540980702.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3218524 + ... + 4105846.
It is an arithmetic number, because the mean of its divisors is an integer number (251588297664).
Almost surely, 23249540980755 is an apocalyptic number.
3249540980755 is a deficient number, since it is larger than the sum of its proper divisors (775871781869).
3249540980755 is a wasteful number, since it uses less digits than its factorization.
3249540980755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 910986.
The product of its (nonzero) digits is 54432000, while the sum is 61.
The spelling of 3249540980755 in words is "three trillion, two hundred forty-nine billion, five hundred forty million, nine hundred eighty thousand, seven hundred fifty-five".
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