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32501000041 = 156072082463
BaseRepresentation
bin11110010001001101…
…011110011101101001
310002220001100212110021
4132101031132131221
51013030224000131
622533013120441
72230255641106
oct362115363551
9102801325407
1032501000041
1112868a70414
126370629121
1330ac584793
141804679aad
15ca34a0e11
hex79135e769

32501000041 has 4 divisors (see below), whose sum is σ = 32503098112. Its totient is φ = 32498901972.

The previous prime is 32501000039. The next prime is 32501000071. The reversal of 32501000041 is 14000010523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32501000041 - 21 = 32501000039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32500999979 and 32501000024.

It is not an unprimeable number, because it can be changed into a prime (32501000071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025625 + ... + 1056838.

It is an arithmetic number, because the mean of its divisors is an integer number (8125774528).

Almost surely, 232501000041 is an apocalyptic number.

It is an amenable number.

32501000041 is a deficient number, since it is larger than the sum of its proper divisors (2098071).

32501000041 is a wasteful number, since it uses less digits than its factorization.

32501000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2098070.

The product of its (nonzero) digits is 120, while the sum is 16.

Adding to 32501000041 its reverse (14000010523), we get a palindrome (46501010564).

The spelling of 32501000041 in words is "thirty-two billion, five hundred one million, forty-one", and thus it is an aban number.

Divisors: 1 15607 2082463 32501000041