325055016671323 has 4 divisors (see below), whose sum is σ = 325056875354848. Its totient is φ = 325053157987800.

The previous prime is 325055016671303. The next prime is 325055016671479. The reversal of 325055016671323 is 323176610550523.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-325055016671323 is a prime.

It is a super-3 number, since 3×325055016671323³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (325055016671303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 929079411 + ... + 929429212.

It is an arithmetic number, because the mean of its divisors is an integer number (81264218838712).

Almost surely, 2^{325055016671323} is an apocalyptic number.

325055016671323 is a deficient number, since it is larger than the sum of its proper divisors (1858683525).

325055016671323 is a wasteful number, since it uses less digits than its factorization.

325055016671323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1858683524.

The product of its (nonzero) digits is 3402000, while the sum is 49.

The spelling of 325055016671323 in words is "three hundred twenty-five trillion, fifty-five billion, sixteen million, six hundred seventy-one thousand, three hundred twenty-three".