Base | Representation |
---|---|
bin | 100100111101011101001011… |
… | …0001100010011011011010001 |
3 | 1120122002210211101112221220121 |
4 | 1021322322112030103123101 |
5 | 320103013111210423441 |
6 | 3111235310401310241 |
7 | 125323055105212006 |
oct | 11172722614233321 |
9 | 1518083741487817 |
10 | 325105774311121 |
11 | 94652648121571 |
12 | 30567816035381 |
13 | 10c5345c67838b |
14 | 5a3d2bc31b8ad |
15 | 278bb32057dd1 |
hex | 127ae963136d1 |
325105774311121 has 4 divisors (see below), whose sum is σ = 325113816945472. Its totient is φ = 325097731676772.
The previous prime is 325105774311107. The next prime is 325105774311137. The reversal of 325105774311121 is 121113477501523.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 325105774311121 - 215 = 325105774278353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (325105774111121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4021256541 + ... + 4021337386.
It is an arithmetic number, because the mean of its divisors is an integer number (81278454236368).
Almost surely, 2325105774311121 is an apocalyptic number.
It is an amenable number.
325105774311121 is a deficient number, since it is larger than the sum of its proper divisors (8042634351).
325105774311121 is an equidigital number, since it uses as much as digits as its factorization.
325105774311121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8042634350.
The product of its (nonzero) digits is 176400, while the sum is 43.
The spelling of 325105774311121 in words is "three hundred twenty-five trillion, one hundred five billion, seven hundred seventy-four million, three hundred eleven thousand, one hundred twenty-one".
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