Base | Representation |
---|---|
bin | 1001011101100110011… |
… | …10100101001110010001 |
3 | 1011002012211111110021210 |
4 | 10232303032211032101 |
5 | 20311331122210340 |
6 | 405210141210333 |
7 | 32330004035451 |
oct | 4566316451621 |
9 | 1132184443253 |
10 | 325129491345 |
11 | 11598313806a |
12 | 530192609a9 |
13 | 24876133209 |
14 | 11a44795d61 |
15 | 86cd90e180 |
hex | 4bb33a5391 |
325129491345 has 16 divisors (see below), whose sum is σ = 524303308800. Its totient is φ = 172037021184.
The previous prime is 325129491277. The next prime is 325129491347. The reversal of 325129491345 is 543194921523.
325129491345 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 325129491345 - 219 = 325128967057 is a prime.
It is a super-2 number, since 2×3251294913452 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 325129491294 and 325129491303.
It is not an unprimeable number, because it can be changed into a prime (325129491347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85333920 + ... + 85337729.
It is an arithmetic number, because the mean of its divisors is an integer number (32768956800).
Almost surely, 2325129491345 is an apocalyptic number.
It is an amenable number.
325129491345 is a deficient number, since it is larger than the sum of its proper divisors (199173817455).
325129491345 is a wasteful number, since it uses less digits than its factorization.
325129491345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170671784.
The product of its digits is 1166400, while the sum is 48.
The spelling of 325129491345 in words is "three hundred twenty-five billion, one hundred twenty-nine million, four hundred ninety-one thousand, three hundred forty-five".
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