325146001537 has 4 divisors (see below), whose sum is σ = 371595430336. Its totient is φ = 278696572740.

The previous prime is 325146001489. The next prime is 325146001541. The reversal of 325146001537 is 735100641523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 735100641523 = 7639 ⋅96229957.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-325146001537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 325146001496 and 325146001505.

It is not an unprimeable number, because it can be changed into a prime (325146001937) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23224714389 + ... + 23224714402.

It is an arithmetic number, because the mean of its divisors is an integer number (92898857584).

Almost surely, 2^325146001537 is an apocalyptic number.

It is an amenable number.

325146001537 is a deficient number, since it is larger than the sum of its proper divisors (46449428799).

325146001537 is an equidigital number, since it uses as much as digits as its factorization.

325146001537 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46449428798.

The product of its (nonzero) digits is 75600, while the sum is 37.

The spelling of 325146001537 in words is "three hundred twenty-five billion, one hundred forty-six million, one thousand, five hundred thirty-seven".