Base | Representation |
---|---|
bin | 100100111110011100101101… |
… | …1000011101110101100010011 |
3 | 1120122120212000121101010022212 |
4 | 1021330321123003232230103 |
5 | 320112232032104124420 |
6 | 3111422114055022335 |
7 | 125335655303254520 |
oct | 11174713303565423 |
9 | 1518525017333285 |
10 | 325242221161235 |
11 | 946a54a68865a4 |
12 | 3058a15596a9ab |
13 | 10c63296081a01 |
14 | 5a45b43ab4147 |
15 | 279046ad6e3c5 |
hex | 127ce5b0eeb13 |
325242221161235 has 128 divisors (see below), whose sum is σ = 514880018104320. Its totient is φ = 192063767486976.
The previous prime is 325242221161219. The next prime is 325242221161237. The reversal of 325242221161235 is 532161122242523.
It is not a de Polignac number, because 325242221161235 - 24 = 325242221161219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 325242221161192 and 325242221161201.
It is not an unprimeable number, because it can be changed into a prime (325242221161237) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 17651564 + ... + 31017126.
It is an arithmetic number, because the mean of its divisors is an integer number (4022500141440).
Almost surely, 2325242221161235 is an apocalyptic number.
325242221161235 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
325242221161235 is a deficient number, since it is larger than the sum of its proper divisors (189637796943085).
325242221161235 is a wasteful number, since it uses less digits than its factorization.
325242221161235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13365697.
The product of its digits is 345600, while the sum is 41.
The spelling of 325242221161235 in words is "three hundred twenty-five trillion, two hundred forty-two billion, two hundred twenty-one million, one hundred sixty-one thousand, two hundred thirty-five".
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