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32525145341123 = 130092500203347
BaseRepresentation
bin1110110010100110110011…
…01110111111110011000011
311021011101002022011000001012
413121103121232333303003
513230342444201403443
6153101502343231135
76564602264552231
oct731233156776303
9137141068130035
1032525145341123
11a3aa922686296
1237937114484ab
13151c1534b5056
1480632283b951
153b60c121b118
hex1d94d9bbfcc3

32525145341123 has 4 divisors (see below), whose sum is σ = 32527645557480. Its totient is φ = 32522645124768.

The previous prime is 32525145341119. The next prime is 32525145341177. The reversal of 32525145341123 is 32114354152523.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 32525145341123 - 22 = 32525145341119 is a prime.

It is a super-2 number, since 2×325251453411232 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32525145341113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1250088665 + ... + 1250114682.

It is an arithmetic number, because the mean of its divisors is an integer number (8131911389370).

Almost surely, 232525145341123 is an apocalyptic number.

32525145341123 is a deficient number, since it is larger than the sum of its proper divisors (2500216357).

32525145341123 is a wasteful number, since it uses less digits than its factorization.

32525145341123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2500216356.

The product of its digits is 432000, while the sum is 41.

Adding to 32525145341123 its reverse (32114354152523), we get a palindrome (64639499493646).

The spelling of 32525145341123 in words is "thirty-two trillion, five hundred twenty-five billion, one hundred forty-five million, three hundred forty-one thousand, one hundred twenty-three".

Divisors: 1 13009 2500203347 32525145341123