Base | Representation |
---|---|
bin | 100100111111010111000001… |
… | …0011100101010101011011001 |
3 | 1120200000211020001022002222220 |
4 | 1021332232002130222223121 |
5 | 320121310002112431101 |
6 | 3111555423040534253 |
7 | 125351010244330506 |
oct | 11176560234525331 |
9 | 1520024201262886 |
10 | 325367436061401 |
11 | 94743611388368 |
12 | 305aa480021389 |
13 | 10c7202c79b006 |
14 | 5a4bc2185c4ad |
15 | 2793848a7a636 |
hex | 127eb8272aad9 |
325367436061401 has 8 divisors (see below), whose sum is σ = 434005756820064. Its totient is φ = 216820369671840.
The previous prime is 325367436061391. The next prime is 325367436061441. The reversal of 325367436061401 is 104160634763523.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 325367436061401 - 26 = 325367436061337 is a prime.
It is a super-3 number, since 3×3253674360614013 (a number of 45 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (325367436061441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22813583955 + ... + 22813598216.
It is an arithmetic number, because the mean of its divisors is an integer number (54250719602508).
Almost surely, 2325367436061401 is an apocalyptic number.
It is an amenable number.
325367436061401 is a deficient number, since it is larger than the sum of its proper divisors (108638320758663).
325367436061401 is a wasteful number, since it uses less digits than its factorization.
325367436061401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45627184551.
The product of its (nonzero) digits is 6531840, while the sum is 51.
The spelling of 325367436061401 in words is "three hundred twenty-five trillion, three hundred sixty-seven billion, four hundred thirty-six million, sixty-one thousand, four hundred one".
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