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325450467113 = 1392341370267
BaseRepresentation
bin1001011110001100101…
…11000000011100101001
31011010001012110201021012
410233012113000130221
520313010304421423
6405302044553305
732340652220042
oct4570627003451
91133035421235
10325450467113
111160283389a2
12530a8852835
13248c77965c5
1411a752698c9
1586ebbb3078
hex4bc65c0729

325450467113 has 4 divisors (see below), whose sum is σ = 327791837520. Its totient is φ = 323109096708.

The previous prime is 325450467101. The next prime is 325450467137. The reversal of 325450467113 is 311764054523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311764054523 = 793946380437.

It is a cyclic number.

It is not a de Polignac number, because 325450467113 - 238 = 50572560169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (325450467163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1170684995 + ... + 1170685272.

It is an arithmetic number, because the mean of its divisors is an integer number (81947959380).

Almost surely, 2325450467113 is an apocalyptic number.

It is an amenable number.

325450467113 is a deficient number, since it is larger than the sum of its proper divisors (2341370407).

325450467113 is a wasteful number, since it uses less digits than its factorization.

325450467113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2341370406.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 325450467113 in words is "three hundred twenty-five billion, four hundred fifty million, four hundred sixty-seven thousand, one hundred thirteen".

Divisors: 1 139 2341370267 325450467113