Base | Representation |
---|---|
bin | 1001011110010010101… |
… | …00110001101100100011 |
3 | 1011010011200002010020101 |
4 | 10233021110301230203 |
5 | 20313111023322201 |
6 | 405311023123231 |
7 | 32342125111615 |
oct | 4571124615443 |
9 | 1133150063211 |
10 | 325500214051 |
11 | 116053426571 |
12 | 53101443517 |
13 | 24904b9376c |
14 | 11a7bad8db5 |
15 | 870123cd01 |
hex | 4bc9531b23 |
325500214051 has 4 divisors (see below), whose sum is σ = 333439243704. Its totient is φ = 317561184400.
The previous prime is 325500214049. The next prime is 325500214093. The reversal of 325500214051 is 150412005523.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 325500214051 - 21 = 325500214049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (325500214001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3969514765 + ... + 3969514846.
It is an arithmetic number, because the mean of its divisors is an integer number (83359810926).
Almost surely, 2325500214051 is an apocalyptic number.
325500214051 is a deficient number, since it is larger than the sum of its proper divisors (7939029653).
325500214051 is an equidigital number, since it uses as much as digits as its factorization.
325500214051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7939029652.
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 325500214051 its reverse (150412005523), we get a palindrome (475912219574).
The spelling of 325500214051 in words is "three hundred twenty-five billion, five hundred million, two hundred fourteen thousand, fifty-one".
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