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32552350051 = 132504026927
BaseRepresentation
bin11110010100010001…
…010111000101100011
310010000121222201102111
4132110101113011203
51013131400200201
622542045500151
72231451260434
oct362421270543
9103017881374
1032552350051
1112894a53441
126385871657
1330ba0c34c0
14180b40548b
15ca7c45b51
hex794457163

32552350051 has 4 divisors (see below), whose sum is σ = 35056376992. Its totient is φ = 30048323112.

The previous prime is 32552350049. The next prime is 32552350121. The reversal of 32552350051 is 15005325523.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 32552350051 - 21 = 32552350049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32552349995 and 32552350022.

It is not an unprimeable number, because it can be changed into a prime (32552350351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1252013451 + ... + 1252013476.

It is an arithmetic number, because the mean of its divisors is an integer number (8764094248).

Almost surely, 232552350051 is an apocalyptic number.

32552350051 is a deficient number, since it is larger than the sum of its proper divisors (2504026941).

32552350051 is a wasteful number, since it uses less digits than its factorization.

32552350051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2504026940.

The product of its (nonzero) digits is 22500, while the sum is 31.

Adding to 32552350051 its reverse (15005325523), we get a palindrome (47557675574).

The spelling of 32552350051 in words is "thirty-two billion, five hundred fifty-two million, three hundred fifty thousand, fifty-one".

Divisors: 1 13 2504026927 32552350051