3255350433 has 4 divisors (see below), whose sum is σ = 4340467248. Its totient is φ = 2170233620.

The previous prime is 3255350377. The next prime is 3255350453. The reversal of 3255350433 is 3340535523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3255350433 - 2⁸ = 3255350177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3255350394 and 3255350403.

It is not an unprimeable number, because it can be changed into a prime (3255350453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542558403 + ... + 542558408.

It is an arithmetic number, because the mean of its divisors is an integer number (1085116812).

Almost surely, 2^3255350433 is an apocalyptic number.

It is an amenable number.

3255350433 is a deficient number, since it is larger than the sum of its proper divisors (1085116815).

3255350433 is a wasteful number, since it uses less digits than its factorization.

3255350433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1085116814.

The product of its (nonzero) digits is 81000, while the sum is 33.

The square root of 3255350433 is about 57055.6783589504. The cubic root of 3255350433 is about 1482.0604417135.

Adding to 3255350433 its reverse (3340535523), we get a palindrome (6595885956).

The spelling of 3255350433 in words is "three billion, two hundred fifty-five million, three hundred fifty thousand, four hundred thirty-three".