Base | Representation |
---|---|
bin | 1111000000011011100001… |
… | …01000001110110111010001 |
3 | 11022211210002100000211220001 |
4 | 13200031300220032313101 |
5 | 13311133223033030001 |
6 | 154104014122050001 |
7 | 6644115551054062 |
oct | 740156050166721 |
9 | 138753070024801 |
10 | 33000123330001 |
11 | a573301343453 |
12 | 384b78a649901 |
13 | 1554b8a690989 |
14 | 8213007c8569 |
15 | 3c3620280001 |
hex | 1e0370a0edd1 |
33000123330001 has 4 divisors (see below), whose sum is σ = 33004164004672. Its totient is φ = 32996082655332.
The previous prime is 33000123329977. The next prime is 33000123330059. The reversal of 33000123330001 is 10003332100033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 33000123330001 - 215 = 33000123297233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33000123330701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2020325085 + ... + 2020341418.
It is an arithmetic number, because the mean of its divisors is an integer number (8251041001168).
Almost surely, 233000123330001 is an apocalyptic number.
It is an amenable number.
33000123330001 is a deficient number, since it is larger than the sum of its proper divisors (4040674671).
33000123330001 is an equidigital number, since it uses as much as digits as its factorization.
33000123330001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4040674670.
The product of its (nonzero) digits is 486, while the sum is 19.
Adding to 33000123330001 its reverse (10003332100033), we get a palindrome (43003455430034).
The spelling of 33000123330001 in words is "thirty-three trillion, one hundred twenty-three million, three hundred thirty thousand, one".
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