Base | Representation |
---|---|
bin | 100101100001000110001111… |
… | …0011000110001110010001011 |
3 | 1121021110002211121020200202201 |
4 | 1023002030132120301302023 |
5 | 321223242322413000021 |
6 | 3125505520450541031 |
7 | 126340011510441361 |
oct | 11302143630616213 |
9 | 1537402747220681 |
10 | 330004322000011 |
11 | 9617105763510a |
12 | 3101906b897777 |
13 | 1121a374097109 |
14 | 5b6c419bd5631 |
15 | 2824282cb5591 |
hex | 12c231e631c8b |
330004322000011 has 4 divisors (see below), whose sum is σ = 330033921466000. Its totient is φ = 329974722534024.
The previous prime is 330004321999991. The next prime is 330004322000027. The reversal of 330004322000011 is 110000223400033.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 330004322000011 - 219 = 330004321475723 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (330004322000911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14799716271 + ... + 14799738568.
It is an arithmetic number, because the mean of its divisors is an integer number (82508480366500).
Almost surely, 2330004322000011 is an apocalyptic number.
330004322000011 is a deficient number, since it is larger than the sum of its proper divisors (29599465989).
330004322000011 is a wasteful number, since it uses less digits than its factorization.
330004322000011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29599465988.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 330004322000011 its reverse (110000223400033), we get a palindrome (440004545400044).
The spelling of 330004322000011 in words is "three hundred thirty trillion, four billion, three hundred twenty-two million, eleven", and thus it is an aban number.
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