Base | Representation |
---|---|
bin | 100101100001001010000000… |
… | …0000111111101100101110001 |
3 | 1121021110212200212100111121122 |
4 | 1023002110000013331211301 |
5 | 321223410400434210113 |
6 | 3125513334444432025 |
7 | 126340416010211036 |
oct | 11302240007754561 |
9 | 1537425625314548 |
10 | 330012404210033 |
11 | 96174524853126 |
12 | 3101a746548615 |
13 | 1121b0616624cc |
14 | 5b6c98537d38d |
15 | 28245a75ee408 |
hex | 12c25001fd971 |
330012404210033 has 4 divisors (see below), whose sum is σ = 338061487239588. Its totient is φ = 321963321180480.
The previous prime is 330012404210011. The next prime is 330012404210057.
330012404210033 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 35266411733809 + 294745992476224 = 5938553^2 + 17168168^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-330012404210033 is a prime.
It is a super-2 number, since 2×3300124042100332 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 330012404209984 and 330012404210011.
It is not an unprimeable number, because it can be changed into a prime (330012404210063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4024541514716 + ... + 4024541514797.
It is an arithmetic number, because the mean of its divisors is an integer number (84515371809897).
Almost surely, 2330012404210033 is an apocalyptic number.
It is an amenable number.
330012404210033 is a deficient number, since it is larger than the sum of its proper divisors (8049083029555).
330012404210033 is an equidigital number, since it uses as much as digits as its factorization.
330012404210033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8049083029554.
The product of its (nonzero) digits is 5184, while the sum is 26.
It can be divided in two parts, 33001240 and 4210033, that added together give a palindrome (37211273).
The spelling of 330012404210033 in words is "three hundred thirty trillion, twelve billion, four hundred four million, two hundred ten thousand, thirty-three".
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