Base | Representation |
---|---|
bin | 110000000001101001011… |
… | …100101100101101111001 |
3 | 102200111122212020211021110 |
4 | 300001221130230231321 |
5 | 413033010311423301 |
6 | 11004045544430533 |
7 | 460303416155265 |
oct | 60015134545571 |
9 | 12614585224243 |
10 | 3300304014201 |
11 | 1062718639387 |
12 | 453755178449 |
13 | 1ac2a963376c |
14 | b5a425750a5 |
15 | 5acad9560d6 |
hex | 3006972cb79 |
3300304014201 has 4 divisors (see below), whose sum is σ = 4400405352272. Its totient is φ = 2200202676132.
The previous prime is 3300304014181. The next prime is 3300304014229. The reversal of 3300304014201 is 1024104030033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a de Polignac number, because none of the positive numbers 2k-3300304014201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3300304014901) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550050669031 + ... + 550050669036.
It is an arithmetic number, because the mean of its divisors is an integer number (1100101338068).
Almost surely, 23300304014201 is an apocalyptic number.
It is an amenable number.
3300304014201 is a deficient number, since it is larger than the sum of its proper divisors (1100101338071).
3300304014201 is a wasteful number, since it uses less digits than its factorization.
3300304014201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1100101338070.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 3300304014201 its reverse (1024104030033), we get a palindrome (4324408044234).
The spelling of 3300304014201 in words is "three trillion, three hundred billion, three hundred four million, fourteen thousand, two hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.101 sec. • engine limits •