Base | Representation |
---|---|
bin | 100101100001010110111001… |
… | …0111111010100111100111001 |
3 | 1121021120112012002222211011210 |
4 | 1023002231302333110330321 |
5 | 321224334111342130131 |
6 | 3125534155045513333 |
7 | 126342416243150001 |
oct | 11302556277247471 |
9 | 1537515162884153 |
10 | 330040101130041 |
11 | 96185247a62065 |
12 | 31023b96112849 |
13 | 11220856844583 |
14 | 5b70051997001 |
15 | 2825178e49146 |
hex | 12c2b72fd4f39 |
330040101130041 has 8 divisors (see below), whose sum is σ = 440059123753920. Its totient is φ = 220023906296432.
The previous prime is 330040101130039. The next prime is 330040101130063. The reversal of 330040101130041 is 140031101040033.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 330040101130041 - 21 = 330040101130039 is a prime.
It is a super-3 number, since 3×3300401011300413 (a number of 45 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (330040101130081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 706675221 + ... + 707142098.
It is an arithmetic number, because the mean of its divisors is an integer number (55007390469240).
Almost surely, 2330040101130041 is an apocalyptic number.
It is an amenable number.
330040101130041 is a deficient number, since it is larger than the sum of its proper divisors (110019022623879).
330040101130041 is a wasteful number, since it uses less digits than its factorization.
330040101130041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1413895135.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 330040101130041 its reverse (140031101040033), we get a palindrome (470071202170074).
The spelling of 330040101130041 in words is "three hundred thirty trillion, forty billion, one hundred one million, one hundred thirty thousand, forty-one".
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