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33004023113 = 113292071001
BaseRepresentation
bin11110101111001100…
…010110110101001001
310011012002220002101102
4132233030112311021
51020043012214423
623054542431145
72245604365505
oct365714266511
9104162802342
1033004023113
1112aa6a02066
126490b924b5
13315c857879
1418513bb305
15cd2714c28
hex7af316d49

33004023113 has 4 divisors (see below), whose sum is σ = 33296094228. Its totient is φ = 32711952000.

The previous prime is 33004023109. The next prime is 33004023119. The reversal of 33004023113 is 31132040033.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31132040033 = 43724000931.

It can be written as a sum of positive squares in 2 ways, for example, as 2388472384 + 30615550729 = 48872^2 + 174973^2 .

It is a cyclic number.

It is not a de Polignac number, because 33004023113 - 22 = 33004023109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33004023119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146035388 + ... + 146035613.

It is an arithmetic number, because the mean of its divisors is an integer number (8324023557).

Almost surely, 233004023113 is an apocalyptic number.

It is an amenable number.

33004023113 is a deficient number, since it is larger than the sum of its proper divisors (292071115).

33004023113 is a wasteful number, since it uses less digits than its factorization.

33004023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 292071114.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 33004023113 its reverse (31132040033), we get a palindrome (64136063146).

The spelling of 33004023113 in words is "thirty-three billion, four million, twenty-three thousand, one hundred thirteen".

Divisors: 1 113 292071001 33004023113