330100113000041 has 4 divisors (see below), whose sum is σ = 330100858342992. Its totient is φ = 330099367657092.

The previous prime is 330100113000037. The next prime is 330100113000061. The reversal of 330100113000041 is 140000311001033.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 330100113000041 - 2² = 330100113000037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 330100112999983 and 330100113000019.

It is not an unprimeable number, because it can be changed into a prime (330100113000061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 372006755 + ... + 372893048.

It is an arithmetic number, because the mean of its divisors is an integer number (82525214585748).

Almost surely, 2^{330100113000041} is an apocalyptic number.

It is an amenable number.

330100113000041 is a deficient number, since it is larger than the sum of its proper divisors (745342951).

330100113000041 is an equidigital number, since it uses as much as digits as its factorization.

330100113000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 745342950.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 330100113000041 its reverse (140000311001033), we get a palindrome (470100424001074).

The spelling of 330100113000041 in words is "three hundred thirty trillion, one hundred billion, one hundred thirteen million, forty-one", and thus it is an aban number.