330100121113121 has 4 divisors (see below), whose sum is σ = 330101654688000. Its totient is φ = 330098587538244.

The previous prime is 330100121113109. The next prime is 330100121113141. The reversal of 330100121113121 is 121311121001033.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 330100121113121 - 2¹⁸ = 330100120850977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 330100121113093 and 330100121113102.

It is not an unprimeable number, because it can be changed into a prime (330100121113141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 766464521 + ... + 766895078.

It is an arithmetic number, because the mean of its divisors is an integer number (82525413672000).

Almost surely, 2^{330100121113121} is an apocalyptic number.

It is an amenable number.

330100121113121 is a deficient number, since it is larger than the sum of its proper divisors (1533574879).

330100121113121 is a wasteful number, since it uses less digits than its factorization.

330100121113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1533574878.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 330100121113121 its reverse (121311121001033), we get a palindrome (451411242114154).

The spelling of 330100121113121 in words is "three hundred thirty trillion, one hundred billion, one hundred twenty-one million, one hundred thirteen thousand, one hundred twenty-one".