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3301300113 = 310914476977
BaseRepresentation
bin1100010011000101…
…1101011110010001
322112001222102101120
43010301131132101
523230113100423
61303330152453
7144544405446
oct30461353621
98461872346
103301300113
111444552701
12781722729
13407c49027
142346379cd
15144c5cee3
hexc4c5d791

3301300113 has 16 divisors (see below), whose sum is σ = 4445823360. Its totient is φ = 2178855936.

The previous prime is 3301300109. The next prime is 3301300133. The reversal of 3301300113 is 3110031033.

3301300113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3301300113 - 22 = 3301300109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3301300092 and 3301300101.

It is not an unprimeable number, because it can be changed into a prime (3301300133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 469681 + ... + 476657.

It is an arithmetic number, because the mean of its divisors is an integer number (277863960).

Almost surely, 23301300113 is an apocalyptic number.

It is an amenable number.

3301300113 is a deficient number, since it is larger than the sum of its proper divisors (1144523247).

3301300113 is a wasteful number, since it uses less digits than its factorization.

3301300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8536.

The product of its (nonzero) digits is 81, while the sum is 15.

The square root of 3301300113 is about 57456.9413822212. The cubic root of 3301300113 is about 1489.0010439958.

Adding to 3301300113 its reverse (3110031033), we get a palindrome (6411331146).

The spelling of 3301300113 in words is "three billion, three hundred one million, three hundred thousand, one hundred thirteen".

Divisors: 1 3 109 327 1447 4341 6977 20931 157723 473169 760493 2281479 10095719 30287157 1100433371 3301300113